可知通项为|1/(n+1)-1/n|
而里面的显然小于0
则原式可化为-(1/2-1)+-(1/3-1/2)+-(1/4-1/3)+…-(1/2010-1/2009)
逐项相消可得 等于
1-1/2010=2009/2010
|1/2-1|+|1/3-1/2|+|1/4-1/3|+…+|1/2010-1/2009|的值是多少?|
2个回答
相关问题
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(-1*1/2)+(-2*1/3)+(-3/1*1/4)+...+(-1/2009*2010)+(-1/2010*1/2
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1/1*2+1/2*3+1/3*4+.1/2009*2010=?
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1/1*2+1/2*3+1/3*4+…+1/2009*2010
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｜1/2-1｜+｜1/3-1/2｜+1/4-1/3｜+...｜1/2009-1/2008｜+｜1/2010-1/2009
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1.-|-3|= 2.+|-3|= 3.-|+3|= 4.|1/2011-1/2010|+|1/2010-1/2009|
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|1/3-1/2|+|1/4-1/3|+...+|1/2010-1/2009|
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(1/2+1/3+1/4+...+1/2010)(1+1/2+1/3+...+1/2009)-（1+1/2+1/3+..
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1/(1*20)+1/(2*3)+1/(3*4).+1/(2009*2010)=?
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计算：|2/1-1|+|3/1-2/1|+|4/1-3/1|.+|2010/1-2009/1|?
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1-1/2）+（1/2-1/3）+（1/3-1/4）.（1/2009-1/2010） = 1-1/2+1/2-1/3+1