(-1/2m^2-1/3mn+1)·(-1/4m^3n)
=(1/2m^2+1/3mn-1)(1/4m^3n)
=(1/2·1/4)m^(2+3)n+(1/3·1/4)m^(1+3)n^(1+1)-1/4m^3n
=(1/8)m^5n+(1/12)m^4n^2-1/4m^3n
(-1/2m^2-1/3mn+1)·(-1/4m^3n)
1个回答
相关问题
-
m=1 mn=2 1/mn+1/(n+1)(m+1)+1/(n+2)(m+2)+1/(n+3)(m+3)...+1/(n
-
1.若m-n=4,mn=1,求（9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
-
1：已知m-n=4,mn=-1,求（-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值?
-
4（-2mn+2m+3n）-2（3m+5n-mn）,其中m+n=3,mn=-1
-
已知m-n=4,mn=-1,求：(2mn+2m+3n)+(3mn+2n-2m)-(m+4n+mn)
-
（4mn²+3m²n-4m)-2(mn²+3/2m²n+1)化简
-
1.已知m+n=3,mn=2,求—3(1/3n—mn)+2(mn—1/2m）.
-
已知m-n=4，mn=-1，求：（-2mn+2m+3n）-（3mn+2n-2m）-（m+4n+mn）的值．
-
已知m-n=4，mn=-1，求：（-2mn+2m+3n）-（3mn+2n-2m）-（m+4n+mn）的值．
-
（m+n)^3+2mn(1-m-n)-1