Question

已知loga2=m(a为底数),loga3=n(a为底数),则,a^(2m+n)=

Answer 1

loga2=m(a为底数),得 a^m = 2

loga3=n(a为底数),得 a^n = 3

a^(2m+n)= (a^m)^2 * a^n = 2^2 * 3 = 12