设甲乙路程为x,原来速度为y:
x/y -x/{(1+20%)y}=25/60.(1)
x/y - 100/y - (x-100)/{(1+20%)y} = 10/60.(2)
化简:
x/y = 5/2.(3)
(x-100)/y = 1.(4)
两式相除得:
x/(x-100)=5/2
5x-500=2x
3x=500
x=500/3
甲乙路程500/3千米
设甲乙路程为x,原来速度为y:
x/y -x/{(1+20%)y}=25/60.(1)
x/y - 100/y - (x-100)/{(1+20%)y} = 10/60.(2)
化简:
x/y = 5/2.(3)
(x-100)/y = 1.(4)
两式相除得:
x/(x-100)=5/2
5x-500=2x
3x=500
x=500/3
甲乙路程500/3千米