4a+4b/5ab*35a^2b/a^2-b^2
1个回答
解
(4a+4b)/(5ab)×(35a²b)/(a²-b²)——这个吧
=4(a+b)/(5ab)×(5ab)(7a)/(a-b)(a+b)
=(4×7a)/(a-b)
=28a/(a-b)
相关问题
计算[(a^2-4b^2)/(a^2+4ab+4b^2)]÷[(a^2+ab-6b^2)/(a^2+5ab+6b^2)]
因式分解:①a(a-b)-b(b-a)②a^5-2a^4+a^3③a^4-3a^2-4④a^2-2ab+b^2-4
1/4a^2b^2(3ab(a+b)-5a(ab-b^2))
a^5-b^5怎么变成(a-b)(a^4+a^3b+a^2b^2+ab^3+b^4)
x3-5x2+5x-4x5+1/4x9a4+11a2b2+4b4(a2-5b2)2+(4ab)2a2-2a+4b-4b2
乘法公式的推广(a-b)(a+b)=a2-b2(a-b)(a2+ab+b2)=a5-b5那么a4-b4a5-b5an-b
(4a-b)(a+b)/(4a^2b-2ab^2)
计算:[(a+b)^2-4ab][(a-b)^2+4ab]-(a^2-b^2)^2
①4a^2+2ab+4a+b+1 ②a^2-4ab+4b^2-2a+4b+1因式分解
已知A=5a^3b+2a^4-3a^2b-ab^3,B=6ab^3-8a^3b+3a^4-5b^4,求2(2A+B)-3