1、已知a-b=5,ab=1求代数式(2a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)的值 2、已知m&

1个回答

  • 1.(2a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)

    =(2a-a+2a)+(3b-4b-2b)+(-2ab-ab-3ab)

    =3a-3b-6ab

    =3*5-6*1

    =9

    2.2m^2+13mn+6n^2-44

    =2(m^2+2mn)+3(3mn+2n^2)-44

    =2*13+3*21-44

    =45

    3.题目有误

    4.a-2b/a+2b=4,所以a+2b/a-2b=1/4

    3(a-2b)/4(a+2b)+3(a+2b)/a-2b

    =3*(3/4)+3*(1/4)

    =15/4

    5.题目有误

    6.x^2=1-x

    x^3+3

    =x*x^2+3

    =x(1-x)+3

    =x-x^2+3

    =x-(1-x)+3

    =2x+2

    题目有误

    7.x:y:z=3:4:5

    那么(4x-5y+2z):(2x-y+z)=(12-20+10):(6-4+5)=2:7

    2x-y-z=10*7/2=35

    8.a/(abc+ab+a+1) +b/(bcd+bc+b+1)+ c/(cda+cd+c+1)+d/(dab+da+d+1)

    =abcd/(bc+b+1+bcd)+b/(bc+bdc+b+1)+abcd/(da+d+1+abd)+d/(dab+da+d+1)

    =(1+b)/(bcd+bc+b+1)+(1+d)/(abd+ad+d+1)

    =(1+b)/(bcd+bc+b+1)+(1+d)bc/(b+1+bcd+bc)

    =[(1+b)+(bc+bcd)]/(b+1+bcd+bc)

    =1