Question

已知x^2-3x+2=0,求(x^2-3X)^2X^2+6X-2的值

Answer 1

题目应是：已知x^2-3x+2=0,求(x^2-3X)^2-2X^2+6X-2的值

已知x^2-3x+2=0,

x^2-3x=-2

(x^2-3X)^2-2X^2+6X-2

=(x^2-3X)^2-2(X^2-3X)-2

=(-2)^2-2*(-2)-2

=4+4-2

=6