第一题:
设农民一共有x个鸡
甲:x/2+1/2=(x+1)/2 剩余x-(x+1)/2=(x-1)/2
乙:(x-1)/4+1/2=(x+1)/4 剩余(x+1)/2-(x+1)/4=(x-3)/4
丙:(x-3)/8+1/2等于乙剩余的(x-3)/4
即:(x-3)/8+1/2=(x-3)/4
解得x=7
答:农民一共有7只鸡.
第一题:
设农民一共有x个鸡
甲:x/2+1/2=(x+1)/2 剩余x-(x+1)/2=(x-1)/2
乙:(x-1)/4+1/2=(x+1)/4 剩余(x+1)/2-(x+1)/4=(x-3)/4
丙:(x-3)/8+1/2等于乙剩余的(x-3)/4
即:(x-3)/8+1/2=(x-3)/4
解得x=7
答:农民一共有7只鸡.