(x-1)(x²+x+1)
=x³+x²+x-x²-x-1
=x³-1
由a-b-3=0 b+1=0 c-1=0 解得a=2 b =-1 c=1
所以(-3ab)(a²b-6b²c)=-2×2×(-1)×【2²×(-1)-6×1×1】=-40
4x²-6x+K= 4(x²-3x/2+k/4)=4(x²-2×x×3/4+k/4) 所以k/4=(3/4)² 得k=9/4
(x-1)(x²+x+1)
=x³+x²+x-x²-x-1
=x³-1
由a-b-3=0 b+1=0 c-1=0 解得a=2 b =-1 c=1
所以(-3ab)(a²b-6b²c)=-2×2×(-1)×【2²×(-1)-6×1×1】=-40
4x²-6x+K= 4(x²-3x/2+k/4)=4(x²-2×x×3/4+k/4) 所以k/4=(3/4)² 得k=9/4