Question

x(2x-1)2-4(x-3)(x2+3x+9)-(9+2x)(9-2x)=0

Answer 1

x(2x-1)^2 -4(x-3)(x^2 +3x+9)-(2x+9)(9-2x)=0

x(4x^2 -4x+1)-(x^2 +3x+9)(4x-12)-(81-4x^2)=0

4x^3 -4x^2 +x-(4x^3 -12x^2 +12x^2 -36x+36x-108)-81+4x^2=0

4x^3 -4x^2 +x-(4x^3 -108)-9+4x^2=0

(4x^3 -4x^3)-(4x^2 -4x^2)+x+108-81=0

化简得 x=-27

所以 该方程解是x=-27