若m^2+n^2-n+4m+17/4=0,m=____,n=_____

3个回答

  • m²+n²-n+4m+17/4=0

    (m+2)²+(n-1/2)²=0

    m=-2,n=1/2

    (1)=4x²-12xy+9y²-9x²+y²=-5x²-12xy+10y²

    (2)=(x²-y²)(x²+y²)=x^4-y^4

    (3)=m²+n²+9-2mn-6m+6n