等差数列(an),(bn)的前n项和为Sn,Tn,且Sn/Tn=2n/3n+1,则a8/b8=?
1个回答
a8/b8=(a1+a15)/(b1+b15).等差中项
S15=15*(a1+a15)/2
T15=15*(b1+b15)/2
a8/b8=S15/T15
=2*15/3*15+1
=15/23
相关问题
等差数列{an},{bn},的前n项和分别为Sn,Tn且Sn/Tn=(3n-1)/(2n+3)则a8/b8=
设数列{An}和{Bn}的前n项和分别为Sn,Tn,且Sn/ Tn=7n+2/n+3,则A8/B8=()
等差数列{an},{bn}的前n项和分别为Sn,Tn,且Sn/Tn=(2n-1)/(3n+2),则a5/b5
等差数列{an},{bn}的前n项和分别为Sn,Tn,且Sn/Tn=(2n+1)/(3n+2),则A12/B15=
等差数列{an}和{bn}的前n项和分别为Sn和Tn,且Sn/Tn=2n/3n+1,则a3/b5=
等差数列{an},{bn}的前n项和分别为Sn,Tn,Sn/Tn=2n/3n+1则a3/b5
设Sn ,Tn分别为等差数列{an}{bn}的前n项和,Sn/Tn=(5n-2)/(n+3),则an/bn=?
等差数列{an},{bn}的前n项分别为Sn,Tn,若Sn/Tn=2n/3n+1,则an/bn=多少?
等差数列{an}和{bn}前n项和为sn,Tn且sn/tn=2n+1/n+2求a5/b5
设数列{an}和{bn}的前n项和 分别为Sn,Tn ,且Sn/Tn=7n+2/n+3,则a8/b8等于