已知f(x)=2sinxcosx+2√3cos²x

已知f(x)=2sinxcosx+2√3cos²x-1-√3,求f(x)的周期

2个回答

f(x)=2sinxcosx+2√3cos²x-1-√3
=sin2x+√3(1+cos2x)-1-√3
=sin2x+√3cos2x-1
=2sin(2x+60°)-1
T=2π/w=2π/2=π