Question

计算：1/(x-1)-1/(x+1)-2/(x²+1)-4/(x的4次方+1)

Answer 1

=（x+1)/(x^2-1)-(x-1)/(x^2-1)-2/(x^2+1)-4/(x^4+1)

=2/(x^2-1)-2/(x^2+1)-4/(x^4+1)

=2(x^2+1)/(x^4-1)-2(x^2-1)/(x^4-1)-4/(x^4+1)

=4/(x^4-1)-4/(x^4+1)

=8/(x^8-1)