Question

已知4x²+y²-4x-6y+10=0求（2/3x（√9x）+(y²√x/y³)

Answer 1

因4x²+y²-4x-6y+10=0

所以

4x²-4x+1+y²-6y+9=0

(2x-1)²+(y-3)²=0

所以2x-1=0,y-3=0

x=1/2,y=3

所以

（2/3x（√9x）+(y²√x/y³)×(x²√1/x×5x√y/x)

=2√x+√(xy)×5x²√y

=2√x+5x²y√x

=(2+5x²y)√x

=(2+15/4)√(1/2)

=23√2/8