其实这4个方程是同一组解
联立
3x-5y=16(1)
2x+5y=-6(2)
(1)+(2)
5x=10
x=2
y=-2
代入含有a和b的方程
2a+2b=-4(3)
2b-2a=-8(4)
(3)+(4)
4b=-12
b=-3
a=1
1)(a-b)×(b-a)²×(b-a)³
=-(a-b)(a-b)²(a-b)^3
=-(a-b)^6
(2)(-a)²×a³×(-a)的5次方×a的6次方×(-a)的7次方
=a^2*a^3*a^5*a^6*a^7
=a^(2+3+5+6+7)
=a^23
(3)2x的n次方× x的(n-2)次方减x的(n-1)次方× x的(n-1)次方减x的(n+1)次方× x的(n-3)次方
=2x^n*x^(n-2)-x^(n-1)*x^(n-1)-x^(n+1)*x^(n-3)
=2x^(2n-2)-x^(2n-2)-x^(2n-2)
=0
(4)(2x-1)(4x²+1)(2x+1)(16x的4次方+1)
=(4x²-1)(4x²+1)(16x^4+1)
=(16x^4-1)(16x^4+1)
=256x^8-1
(5)(a-2b+3c)²-(a+2b-3c)²
=(a-2b+3c+a+2b-3c)(a-2b+3c-a-2b+3c)
=2a*(6c-4b)
=4a(3c-2b)