t1时,a2=2a1=2a, s1=a(t1)^2/2, s2=2a(t1)^2/2
t2时,a1'=2a,a2'=a,s1'=2a(t2)^2/2,s2'=a(t2)^2/2
∵t1=t2=t
∴s1总：s2总=a[(t1)^2/2+(t2)^2]：a[(t1)^2+(t1)^2/2]
=[3/2*(t)^2]：[3/2*(t)^2]=1
即在这两段时间内,两车走过的总路程相等.
=[(t1)^2+2(t2)^2]：[2(t1)^2+(t1)^2]
t1时,a2=2a1=2a, s1=a(t1)^2/2, s2=2a(t1)^2/2
t2时,a1'=2a,a2'=a,s1'=2a(t2)^2/2,s2'=a(t2)^2/2
∵t1=t2=t
∴s1总：s2总=a[(t1)^2/2+(t2)^2]：a[(t1)^2+(t1)^2/2]
=[3/2*(t)^2]：[3/2*(t)^2]=1
即在这两段时间内,两车走过的总路程相等.
=[(t1)^2+2(t2)^2]：[2(t1)^2+(t1)^2]