Question

函数y=√2sin(2x-π)cos{2(x+π)}的周期,奇偶性

Answer 1

y=√2sin(2x-π)cos{2(x+π)}＝-√2sin2xcos2x＝-√2/2sin4x

T=2π/4=π/2

因y=sin4x是奇函数

y=√2sin(2x-π)cos{2(x+π)是奇函数}