Question

(x+1分之x平方-4)的平方除以(x的平方-1分之x平方-2x+1)×(x+2分之x)的三次方其中x=-1.

Answer 1

[(x²-4)/(x+1)]²÷[(x²-2x+1)/(x²-1)]*[x/(x+2)]³

=[(x+2)(x-2)/(x+1)]²÷[(x-1)²/(x+1)(x-1)]*[x³/(x+2)³]

=[(x+2)²(x-2)²/(x+1)²]÷[(x-1)/(x+1)]*[x³/(x+2)³]

=[(x+2)²(x-2)²/(x+1)²]*[(x+1)/(x-1)]*[x³/(x+2)³]

=[x³(x-2)²]/[(x+1)(x+2)]

因为此题中分母x+1≠ 0,所以x≠ -1.所以题目有误

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