先因式分x^2+2x-3=(x-1)(x+3)；-x^2+x+6=-(x-3)(x+2)
所以原不等式可变为：(x-1)(x+3)/[-(x-3)(x+2)]0
等价于：(x-1)(x+3)(x-3)(x+2)>0
利用数轴标根法,可得：x>3或-2
先因式分x^2+2x-3=(x-1)(x+3)；-x^2+x+6=-(x-3)(x+2)
所以原不等式可变为：(x-1)(x+3)/[-(x-3)(x+2)]0
等价于：(x-1)(x+3)(x-3)(x+2)>0
利用数轴标根法,可得：x>3或-2