已知椭圆x^2/a^2+y^2/b^2=1(a>b>0)上一点P(3,4),若PF⊥PE,试求椭圆方程

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  • 用矢量,内积为0

    根据条件就可以了

    P,Q的坐标用(x1,-x1-1),(x2,-x2-1)

    则x1x2+x1x2+x1+x2+1=0.(*)

    a^2=2c^2,b^2=c^2

    x1^2/2c^2+y1^2/c^2=1.(1)

    x2^2/2c^2+y2^2/c^2=1.(2)

    (2)-(1)

    (x1^2-x2^2)/2c^2+(y1+y2)(y1-y2)/c^2=0

    (x1^2-x2^2)/2c^2+(-x1-x2-2)(x2-x1)/c^2=0.(3)

    由(*),(3)

    ((x1-x2)(1.5(x1+x2)+2))/c^2=0

    即:(x1-x2)(1.5(x1+x2)+2)=0.(4)

    由(*)和(4)

    (0.5-3x1x2)(x1-x2)=0

    显然x1!=x2

    x1x2=1/6,x1+x2=-4/3

    (1)+(2)

    (x1^2+x2^2)/2c^2+(y1^2+y2^2)/c^2=2

    ((x1+x2)^2-2x1x2)/2c^2+((-x1-x2-2)^2-2(x1+1)(x2+1))/c^2=2

    即:

    (16/9-1/3)/2c^2+((4/3-2)^2-2(1/6-4/3+1))/c^2=2

    即:

    (13/18c^2+14/18c^2=2

    c^2=3/4

    a^2=3/2,b^2=3/4

    椭圆x^2/(3/2)+y^2/(3/4)=1