Question

如图,角A+角B+角C+角D+角E+角F的度数

Answer 1

∵∠A+∠B=∠AIC,∠C+∠D=∠APB,∠E+∠F=∠AOE

∴∠A+∠B∠C+∠D+∠E+∠F

=∠AIC+∠APB+∠AOE

=（180°-∠OIP)+(180°-∠OPI)+(180°-∠POI)

=180°×3-(∠OIP+∠OPI+∠POI)

=540°-180°

=360°