Question

弓形的弦AB=6√3,弓形的高为9,求弓形面积

Answer 1

设弓形所在的圆的半径为r,则

r^2=(9-r)^2+(3√3)^2===>r=6

弓形面积=π*r^2-((1/2)*2π/3*r^2-(1/2)*6√3*(9-r))=24π-9√3