(1)由题意,得
95×0.88-80=3.6元,
n(60×0.92-50)=5.2n元,
故答案为:3.6,5.2n
(2)设该中学买了篮球x个,则排球(50-x)个,当0<x<26时,
(95×0.95-80)x+(60×0.9-50)(50-x)=305,
解得:x=16.8(不符合题意,舍去)
当x≥26时,
(95×0.9-80)x+(60×0.95-50)(50-x)=305,
解得x=30,
∴排球买了50-30=20个
答:篮球买了30个,排球买了20个.
(1)由题意,得
95×0.88-80=3.6元,
n(60×0.92-50)=5.2n元,
故答案为:3.6,5.2n
(2)设该中学买了篮球x个,则排球(50-x)个,当0<x<26时,
(95×0.95-80)x+(60×0.9-50)(50-x)=305,
解得:x=16.8(不符合题意,舍去)
当x≥26时,
(95×0.9-80)x+(60×0.95-50)(50-x)=305,
解得x=30,
∴排球买了50-30=20个
答:篮球买了30个,排球买了20个.