若a^2n=5,求a^6n怎么算?
1个回答
a^6n
=a^(2n×3)
=(a^2n)^3
=5^3
=125
相关问题
若2^m=a,2^n=b,则2^m+n=?怎么算?
若a≠-2,求(n→∞)lim(2^n-a^n)/[2^n+a^(n+1)]
(6+n)(5/6)^n的极限怎么算
a^2n=4,求(2a^3n)^2-6a^4n+1(-5a^4n-1)的值
已知数列{an}满足a1=5,a2=5,a(n+1)=an+6a(n-1),(n≥2,n属于正整数),若数列{a(n+1
1已知a^2n=4,求(2a^3n)^2-(6a^4n+1)*(-5a^4n-1)
1+2-3+4-5+6.+n怎么算
若lim(5n+4)a[n]=5,求lima[n]和limna[n]
已知数列{a(n)}中,a(1)=1,a(2)=5,a(n+1)=5a(n)-6a(n-1) 【n>=2,n属于n*】
若(a^m+1b^n+2)·(a^2n-1·b)=a^5b^4,求m+n的值.