Cu(OH)2的Ksp=2.2*10^-20
Cu(OH)2+2H+=Cu2++2H2O
K=[Cu2+]/[H+]^2,上下乘以[OH-]^2
K=[Cu2+][OH-]^2/[H+]^2[OH-]^2=Ksp/Kw^2
=2.2*10^-20/10^-28
=2.2*10^8=[Cu2+]/[H+]^2
[H+]^2=[Cu2+]/2.2*10^8,假设铜离子浓度=0.1摩尔/升,[H+]^2=0.1/2.2*10^8=4.5*10^-10
[H+]=2.1*10^-5,PH=4.68.
氢氧化铜的溶解PH大约在4.7以下