Question

物质的量浓度计算题9.用密度为ρ1 g•cm－3,质量分数为n％的浓盐酸,配制成体积比为1∶4的稀HCl(稀盐酸的密度为

Answer 1

设所用浓HCl体积为1L,水的体积为4L

n(HCl)=ρ1 g•cm－3*1000ml*n%/36.5=10ρ1n/36.5

V总＝(ρ1g•cm－3*1000ml+1g•cm－3*4000ml)/(ρ2 g•cm－3)

=(1000ρ1+4000)/ρ2ml==(ρ1+4)/ρ2L

c=n(HCl)/V总=10 ρ1ρ2n／36．5 (ρ1＋4)mol•L－1