题目很简单,2^n=偶数,2^n+1=奇数,而2^2+1=5,5与所有奇数的积的个位数一定是5.
2^1=2,2^2=4,2^3=8,2^4=16,2^5=32,设A=（2+1）（2^2+1）(2^4+1).(2^16
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（2+1)(2²+1)(2^4+1)(2^8+1）（2^16+1）（2^32+1）的解