B=30°
AB=2√3
AC=2
做AD⊥BC于D
BD=ABcosB=2√3*√3/2=3
AD=ABsinB=2√3*sin30°=2√3*1/2=√3
sinACD=AD/AC=√3/2
ACD=60°
CD=ACcos60°=2*1/2=1
BC=BD±CD=3±1=2,或4
SABC=1/2BC*AD=1/2BC*√3=√3/2 BC = √3,或2√3
B=30°
AB=2√3
AC=2
做AD⊥BC于D
BD=ABcosB=2√3*√3/2=3
AD=ABsinB=2√3*sin30°=2√3*1/2=√3
sinACD=AD/AC=√3/2
ACD=60°
CD=ACcos60°=2*1/2=1
BC=BD±CD=3±1=2,或4
SABC=1/2BC*AD=1/2BC*√3=√3/2 BC = √3,或2√3