Private Sub Command1_Click()
Cls
s = "0123456789ABCDEFG"
y = s: x = s
Do Until Len(s) = 1
i = i + 1
If i Mod 3 = 0 Then s = Replace(s, Mid(y, i, 1), "") '删除报到3的倍数的号
If i = Len(y) Then y = y & s
Loop
For i = 0 To Len(x) - 1
If s = Mid(x, i + 1, 1) Then Print "原位置编号是" & i
Next i
End Sub
答案是10号,就是一开始报数报11的那个人