f（x)=sin(2x+π/6)+2sin(x-π/4)sin(x+π/4)
=sin(2x+π/6)+cos[(x-π/4)-(x+π/4)]-cos[(x-π/4)+(x+π/4)]
=sin(2x+π/6)+cos(-π/2)-cos2x
=sin(2x+π/6)-cos2x
=sin2x*cos(π/6)+cos2x*sin(π/6)-cos2x
=sin2x*(√3/2)+cos2x*(1/2)-cos2x
=sin2x*(√3/2)-cos2x*(1/2)
=sin2x*cos(π/6)-cos2x*sin(π/6)
=sin(2x-π/6)
如果不懂,祝学习愉快!