整式的除法:12X^5y^6z^4/(-3X^2y^2z^)/(2x^3y^3z^3)
1个回答
原式=(12X^5y^6z^4/-3X^2y^2z^)*(1/2x^3y^3z^3)
=12x^5y^6z^4/(-6x^5y^5z^4)
=-2y
相关问题
2x+5y+4z=6,3x+y-7z=-4,4x+3y+12z=-2 求x+y+z
3x-y+z=4,2x+3y-z=12,x+y+z=6
{3x-y+z=4,2x+3y-z=12,x+y+z=6
2x+y+3z=5 3x-2y-z=6 4x-3y+2z=4
x+y+z=2 ① 2x+3y+z=38 ① x+y=3 3x-y-4z=5 ② 3x+4y+2z+56 ② y+z=5
2x+y-z=9 3x-y+2z=12 5x+3y-3z=12
x-5y-3z=0 y+z-3x=3 x+y+3z=14 y+4z=3 z+x-3y=5 2x+y+z=7 2x-z=1
x-2y+3z=0,3x+2y+5z=12,2x-4y-z=(-9)
解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}
(1)y=2x-7 6x+3y+2z=2 3x-4z=4 (2) 4x+9y=12 3y-2z=1 7x+5z=19/4