Question

已知:如图,直线AB,CD相交于点O,OE平分∠BOD,OF平分∠COB,∠AOD:∠DOE=4:1.求∠AOF

Answer 1

∠AOD：∠DOE=4：1

OE平分∠BOD

则∠AOD：∠DOB=4：2=2 :1

有∠AOD=120 ∠DOB=60

OF平分∠COB

有∠COB=120 ∠FOB=60

则∠AOF=120度