已知log2^64 +log2^x =5 ,则x的值是?
3个回答
log2^64 +log2^x =5
6+log2[x]=5
得 log2[x]=-1
所以
x=1/2
相关问题
已知log2[log0.5(log2X)]=0,求X的值
已知log2(x+y)=log2x+log2y,则x+y的取值范围是( )
已知log2(x+y)=log2x+log2y,则x+y的取值范围是?
已知log2(x+y)=log2x+log2y,则x+y的取值范围是( )
已知log3[log4(log2x)]=0,则x=______.
已知log3【log3(log2x)】=0,则x=( ),
已知log∨7∧[log∨3∧(log∨2∧x)]=0 求X∧1/2的值
已知log(x-2)^2=2log(x-2),则x的取值范围
已知log23*log3|x|=2,求x的值
已知log(a)x=1,log(b)x=2,log(c)x=4,则log(abc)x=?