因式分解、平方差公式进行分解1.x²(y-4)-(y-4)2.2x²-323.已知a+b=8且a&s

2个回答

  • 1.x²(y-4)-(y-4)

    =(x^2-1)(y-4)

    =(x+1)(x-1)(y-4)

    2.2x²-32

    =2(x^2-16)

    =2(x+4)(x-4)

    3.已知a+b=8且a²-b²=48.则a-3b=

    a+b=8

    a^2-b^2=48

    (a+b)(a-b)=48

    a-b=6

    a+b=8

    a=8-b

    把a=8-b代入a-b=6

    8-b-b=6

    8-2b=6

    b=1

    把b=1代入a-b=6

    a-1=6

    a=7

    a-3b=7-3*1=4

    4.x²-4y²

    =(x+2y)(x-2y)

    5.-x²+x²y²

    =-x^2(1-y^2)

    =-x^2(1+y)(1-y)

    6.a²(a-b)+b²(b-a)

    =(a^2-b^2)(a-b)

    =(a+b)(a-b)^2

    7.(a+b)²-(a-b)²

    =(a+b+a-b)(a+b-a+b)

    =2a(2b)

    =4ab

    8.4x²-5

    题目是否有误?

    9.x²-16

    =(x+4)(x-4)

    10.x^3+x²y-xy²-y^3

    =x^2(x+y)-y^2(x+y)

    =(x+y)^2(x-y)

    11.(5m²+3n²)²-(3m²+5n²)²

    =(5m^2+3n^2+3m^2+5n^2)(5m^2+3n^2-3m^2-5n^2)

    =(8m^2+8n^2)(2m^2-2n^2)

    =8(m^2+n^2)*2(m+n)(m-n)

    =16(m+n)(m-n)(m^2+n^2)