sin(a+b)=3/5,cosb=-5/13,所以cos(a+b)=-4/5,sinb=12/13
所以,tan(a+b)=-3/4,tanb=-12/5
tana=tan((a+b)-b)=(tan(a+b)-tanb)/(1+tan(a+b)×tanb)
=(-3/4+12/5)/(1+3/4×12/5)
=33/56
sin(a+b)=3/5,cosb=-5/13,所以cos(a+b)=-4/5,sinb=12/13
所以,tan(a+b)=-3/4,tanb=-12/5
tana=tan((a+b)-b)=(tan(a+b)-tanb)/(1+tan(a+b)×tanb)
=(-3/4+12/5)/(1+3/4×12/5)
=33/56