Question

分式的加减计算：(1/x-y-x^2+y^2)-(1/1-x^2-2xy-y^2) 注：“/”指除号.

Answer 1

1/(x-y-x^2+y^2)-1/(1-x^2-2xy-y^2)

=1/[(x-y)(1-x-y)]-1/[1-(x+y)^2]

=1/[(x-y)(1-x-y)]-1/[(1-x-y)(1+x+y)]

=[1+x+y-(x-y)]/[(x-y)(1-x-y)(1+x+y)]

=(1+2y)/[(x-y)(1-x-y)(1+x+y)]