sin2x-cos2x-1
=√2(sin2x×√2/2-cos2x×√2/2)-1
=√2sin(2x-π/4)-1
如果本题有什么不明白可以追问,
sin2x-cos2x-1=√2 sin(2x-π/4) 这又是怎么化的?
3个回答
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