Question

0.1MOL/L的CH3COOH溶液中滴加NAOH溶液至C(CH3COOH)：C(CH3COO-)=5:9,此时溶液PH

Answer 1

根据电离常数 Ka=1.8*10^-5

K=[c(H+)*c(CH3COO-)]/c(CH3COOH)

c(H+)=K*c(CH3COOH)/c(CH3COO-)=1.8*10^-5*5/9=10^-5

PH=5