Question

解一个二元一次方程,(2000+2000x-1000)(1+x)=1107.45

Answer 1

(2000x+1000)(1+x)=1107.45

1000(2x+1)(1+x)=1107.45

2x+2x^2+1+x=1.10745

2x^2+3x=0.10745

2(x+3/4)^2=0.10745+2*9/16=1.23245

(x+3/4)^2=0.616225

x+3/4=±0.785

x=0.75±0.785

x1=0.75-0.785=-0.035

x2=0.75+0.785=1.535