Question

已知多项式A=ax^5+bx^4+cx^3+dx^2+ex+f与多项式B=bx^4+dx^2+f,当x=1时,多项式A和

Answer 1

4=a+b+c+d+e+f,2=b+d+f.所以a+c+e=4-2=2

x=-1时,多项式A=-a+b-c+d-e+f=-2+2=0