一元二次方程 分解因试法

1个回答

  • (2)3x(x-1)-(2-2x)=0,3x(x-1)+2(x-1)=0,(3x+2)(x-1)=0

    (4)2(x-3)²-(x²-9)=0,2(x-3)²-(x+3)(x-3)=0,(2(x-3)-(x+3))(x-3)=0

    (2x-6-x-3)(x-3)=0,(x-9)(x-3)=0

    (2)(x-2)²-(2x+3)²=0,(x-2-(2x+3)))(x-2+(2x+3))=0

    (x-2-2x-3)(x-2+2x+3)=0,(-x-5)(3x+1)=0即(x+5)(3x+1)=0