求值arcsin(cos3π/7)

1个回答

设arcsin(cos(3π/7))＝θ,则
sinθ＝cos(3π/7)＝sin(π/2-3π/7)＝sin(π/14),
∴θ＝π/14,
即arcsin(cos(3π/7))＝π/14.