Question

y=cos^2(x^2-x)求导,要设u= v=那种

Answer 1

设y=u^2

u=cosv

v=x^2-x

所以,y'=2u*u'

而u'=-sinv*v'

v'=2x-1

得y'=(2-4x)sin(x^2-x)cos(x^2-x)

=(1-2x)sin(2x^2-2x)