分解下列因式:(1) -9+16x²y² (2) (a+b)²-1 (3)a²-

3个回答

  • 分解下列因式:

    (1) -9+16x²y²

    =(4xy+3)(4xy-3)

    (2) (a+b)²-1

    =(a+b-1)(a+b+1)

    (3)a²-4b²

    =(a-2b)(a+2b)

    (4)9(x+2)²-25(x+3)²

    =【3(x+2)+5(x+3)】【3(x+2)-5(x+3)】

    =(3x+6+5x+15)(3x+6-5x-15)

    =(8x+21)(-2x-9)

    =-(8x+21)(2x+9)

    (5)7x的n次方+1-14x的n次方+7x的n-1次方

    =7x的n-1次方(x²-2x+1)

    =7x的n-1次方(x-1)²