Question

(2a+b) (2a-b) (a的2次方+4b的2次方)计算题!过程是必须的,快的呀,

Answer 1

原式=(4a^2-b^2)(a^2+16b^2)

=4a^4+64a^2*b^2-a^2*b^2-16b^4

=4a^4+63a^2*b^2-16b^4