Question

一道关于复合函数偏导数的求解问题,

Answer 1

z = y/f(x² - y²),令u = x² - y²∂z/∂x = y · [- f'(x² - y²) · 2x]/f(x² - y²)² = - 2xyf'(x² - y²)/f(x² - y²)²∂z/...