(2008?达州)如图,一个四边形花坛ABCD,被两条线段MN,EF分成四个部分,分别种上红、黄、紫、白四种花

1个回答

  • 设红、紫四边形的高相等为h1,黄、白四边形的高相等,高为h2

    则S1=DE?h1,S2=AF?h2,S3=EC?h1,S4=FB?h2

    因为DE=AF,EC=FB,

    故A错误;

    S1+S4=DE?h1+FB?h2=AF?h1+FB?h2

    S2+S3=AF?h2+EC?h1=AF?h2+FB?h1

    故B错误;

    S1S4=DE?h1?FB?h2=AF?h1?FB?h2

    S2S3=AF?h2?EC?h1=AF?h2?FB?h1

    所以S1S4=S2S3

    故C正确;

    故选:C.