Question

4a＾2+4ab+b＾2-1((x＾2+1)＾2-x＾2)/(x＾2+x+1) (a＾4-b＾2)/(a+b) (x＾4

Answer 1

((x＾2+1)＾2-x＾2)/(x＾2+x+1)=(x^2+x+1)*(x^2-x+1)/(x＾2+x+1)=x^2-x+1 (a＾4-b＾2)/(a+b)=?是否(a＾4-b＾4)/(a+b)=(a^2+b^2)*(a+b)*(a-b)/(a+b)=(a^2+b^2)*(a+b) (x＾4-2x＾2+1)/(x＾2+2x+1)=(x^2-1)^2/(x+1)^2=(x-1)^2