Question

(x-根号3)平方=4x+12-4根号3 解此方程

Answer 1

(x-根号3)^2=4x+12-4根号3

(x-根号3)^2=4(x-根号3)+12

设X=(x-根号3)

所以

X^2=4X+12

X^2-4X-12=0

(X-6)(X+2)=0

X=6或负2

所以

x-根号3=6,即x=6+根号3

或

x-根号3=-2,即x=负2+根号3